Question

因式分解:a方+b方＋c方+2ab+2ac+2bc

Answer 1

a方+b方＋c方+2ab+2ac+2bc
=（2a方+2b方＋2c方+4ab+4ac+4bc）／2
=[（a方+2ab+b方）+(a方+2ac+c方)+(b方+2bc+c方)]/2
=[(a+b)方+(a+c)方+(b+c)方]/2