Question

帮忙做做因式分解 谢谢

Answer 1

①原式=(2x²-3x+1)²-22x+33-11+10
=(2x²-3x+1)²-11(2x²-3x+1)+10
=[(2x²-3x+1)-1][(2x²-3x+1)-10]
=(2x²-3x)(2x²-3x-9)
=x(2x-3)(x-3)(2x+3)

②原式=(x2+3x+2)(4x2+8x+3)-90
=(x+1)(x+2)(2x+1)(2x+3)-90
=(x+1)(2x+3)(x+2)(2x+1)-90
=(2x²+5x+3)(2x²+5x+2)-90
=(2x²+5x)²+5(2x²+5x)-84
=(2x²+5x+12)(2x²+5x-7)
=(2x²+5x+12)(2x+7)(x-1)

③x^4-7x2+1
=(x2+1)2-9x2
=(x2+1+3x)(x2+1-3x)

④=x^3+2x^2-5x-6
=x^3+x^2+x^2-5x-6
=x^2(x+1)+(x-6)(x+1)
=(x+1)(x^2+x-6)
=(x+1)(x+3)(x-2)

⑤=x^4+2x^2y^2+y^2-x^2y^2+(x+y)^4-x^2y^2
=(x^2+y^2)^2-x^2y^2+(x+y)^4-x^2y^2
=(x^2+y^2+xy)(x^2+y^2-xy)+[(x+y)^2+xy)][(x+y)^2-xy]
=(x^2+y^2+xy)[(x^2+y^2-xy+x^2+y^2+3xy)
=2(x^2+y^2+xy)^2

⑥(6x-1)(2x-1)(3x-1)(x-1)+x^2
=[(6x-1)(x-1)][(2x-1)(3x-1)]+x^2
=[(6x^2+1)-7x][(6x^2+1)-5x]+x^2
=(6x^2+1)^2-12x(6x^2+1)+35x^2+x^2
=(6x^2+1)^2-12x(6x^2+1)+36x^2
=(6x^2+1)^2-2*(6x)*(6x^2+1)+(6x)^2
=(6x^2-6x+1)^2
（ps：你问了两遍,第二次回答了OTZ...）