Question

JAVA以POST方式提交XML获取返回值(返回格式为XML)

我想写一个方法:
String url = "http://123.12.12.12:8909/asdasd";
String xml = "<?xml version="1.0" encoding="utf-8"?><request><hRet>0</hRet><transIDO>12345678901234567</transIDO></request>"

public String toSendXML(String url, String xml){
/*

这里该怎么写 哪位大神帮我下 谢谢了, 我用了网上的好多方法 但是获取不到返回值

*/

}
希望能弄得详细点 在线等 急啊

Answer 1

URL url = new URL(requestUrl);
HttpsURLConnection httpUrlConn = (HttpsURLConnection) url.openConnection();
httpUrlConn.setRequestMethod(“POST”);
OutputStream outputStream = httpUrlConn.getOutputStream();
outputStream.write(xml);
outputStream.close();
InputStream inputStream = httpUrlConn.getInputStream();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
String str = null;
while ((str = bufferedReader.readLine()) != null) {
buffer.append(str);
}
bufferedReader.close();
inputStreamReader.close();
// 释放资源
inputStream.close();
inputStream = null;
httpUrlConn.disconnect();

追问

请问能否再详细点呢 比如buffer.append(str); 的buffer是哪里来的

追答

StringBuffer buffer = new StringBuffer();