初二的数学题，帮忙解答一下吧！！！！！！！！！
2个回答
2013-09-16 · 知道合伙人教育行家
wangcai3882
知道合伙人教育行家
采纳数：20214
获赞数：108207
本人擅长中学阶段数、理、化、生等理科知识，尤其是数学。高中时曾参加全国数学竞赛并获奖，期望能为你答疑
向TA提问 私信TA
关注
![]()
展开全部
解：
[5xy/(x³-x²y)]⁴÷(-5/x²y)⁴*[(y-x)/xy]³
=[5xy/x²(x-y)]⁴*(x²y/5)⁴*[(y-x)/xy]³
=[5xy/x²(x-y)*(x²y/5)]⁴*[(y-x)/xy]³
=[xy²/(x-y)]⁴*[(y-x)/xy]³
=[xy²/(y-x)]³*[(y-x)/xy]³*xy²/(y-x)
=[xy²/(y-x)*(y-x)/xy]³*xy²/(y-x)
=y³*xy²/(y-x)
=xy^5/(y-x)
[5xy/(x³-x²y)]⁴÷(-5/x²y)⁴*[(y-x)/xy]³
=[5xy/x²(x-y)]⁴*(x²y/5)⁴*[(y-x)/xy]³
=[5xy/x²(x-y)*(x²y/5)]⁴*[(y-x)/xy]³
=[xy²/(x-y)]⁴*[(y-x)/xy]³
=[xy²/(y-x)]³*[(y-x)/xy]³*xy²/(y-x)
=[xy²/(y-x)*(y-x)/xy]³*xy²/(y-x)
=y³*xy²/(y-x)
=xy^5/(y-x)
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
