Question

（a的平方+根号2个a+1)(a的平方-根号2个a+1）怎么算？

Answer 1

[a^2+2√ (a+1)] [a^2-2√ (a+1)] =a^4- [2√(a+1)]^2=a^4-4 (a+1)=a^4-4a-4 a^4表示a的4 次方

Answer 2

原式=[a�0�5+（√a+1）][a�0�5-（√a+1）]=a^4-(√2a+1)�0�5=a^4-2a�0�5+2√2a+1

Answer 3

看了这么久，终于知道是[a^2+2√ (a)+1] [a^2-2√ (a)+1]