计算下列题目,要过程
2个回答
2013-09-20 · 知道合伙人教育行家
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计算:
(1)原式=[2×(-35)]×(-3/7)=(-70)×(-3/7)=30
(2)原式=[(-4)×(-2.5)]×0.96=10×0.96=9.6
(3)原式=[(+2/3)×(-9/2)]×5=(-3)×5=-15
(4)原式=[5/6×(-2又2/5)]×[(-1又1/8)×(-4/9)]=(-2)×1/2=-1
用分配律计算:
(1)原式=(-4)×5/4-(-4)×3/2=(-5)+6=1
(2)原式=2/9×27-1/3×27-2/27×27=6-9-2=-5
(3)原式=(-270)×1/4+1/4+(-8又12)×(-1/)=(-270+1+8又1/2)×1/4=(-206又1/2)×1/4=-65又1/8
(1)原式=[2×(-35)]×(-3/7)=(-70)×(-3/7)=30
(2)原式=[(-4)×(-2.5)]×0.96=10×0.96=9.6
(3)原式=[(+2/3)×(-9/2)]×5=(-3)×5=-15
(4)原式=[5/6×(-2又2/5)]×[(-1又1/8)×(-4/9)]=(-2)×1/2=-1
用分配律计算:
(1)原式=(-4)×5/4-(-4)×3/2=(-5)+6=1
(2)原式=2/9×27-1/3×27-2/27×27=6-9-2=-5
(3)原式=(-270)×1/4+1/4+(-8又12)×(-1/)=(-270+1+8又1/2)×1/4=(-206又1/2)×1/4=-65又1/8
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( 1998 / 17 X 119 / 54 ) / ( 29 X 0.5 + 5.7 X 2 )= [ ( 1998 X 119 ) / ( 17 X 54 ) ] / ( 14.5 + 11.4 )= [ ( 222 X 9 X 17 X 7 ) / ( 17 X 9 X 6 ) ] / ( 4.9 + 21 )= [ ( 222 X 7 ) / 6 ] / ( 7 X 3.7 )= [ ( 111 X 7 ) / 3 ] / ( 7 X 3.7 )= ( 37 X 7 ) / ( 7 X 3.7 )= 10 [ (2+ 2/3) + Y ] / (3+ 3/4) - 0.4 = 32/45 ( 8/3 + Y ) / ( 15/4 ) - 2/5 = 32/45 ( 8/3 + Y )( 4/15 ) = 32/45 + 18/45 32/45 + (4/15)Y = 32/45 + 18/45 ( 4/15 )Y = 18/45 ( 2/15 )(2Y) = ( 2/15 )( 9/3 ) 2Y = 3 Y = 1.5 16.8 X [ (2.4+ 1/3) / 1.12 - (1+ 5/6) ]= 8 X 2.1 X [ (7.2/3 + 1/3) / 1.12 - 11/6 ]= 8 X 2pr1 X ( 8.2 / 3 ) X 100/112 - 8 X 21 X 11/6= 8 X 7 X 82 / (56 X 2) - 4 X 2.1 X 11 / 3= 41 - 4 X 11 X 0.7= 41 - 30.8= 10.2 8.4 X [ (1.2 + 3+ 1/3 ) / 3.4 - 1/2 ]= 8.4 X [ ( 3.6/3 + 10/3 ) / 1.7 - 1 ] / 2= 4.2 X [ 13.6 / 5.1 - 5.1 / 5.1 ]= 4.2 X 8.5 / 5.1= 2.1 X 17 / ( 17 X 0.3 )= 7 ( 1+ 7/10 ) / [ (2+ 1/3) - 12/29 X ( 1.7 + 1+ 1/5 ) ] X 0.16= 1.7 / [ 7/3 - 12/29 X ( 1.7 + 1.2 ) ] X 0.16= 1.7 / [ 7/3 - 1.2/2.9 X 2.9 ] X 0.16= 1.7 / [ 7/3 - 1.2 ] X 0.16= 1.7 / [ 7/3 - 3.6/3 ] X 0.16= 1.7 / ( 3.4 / 3 ) X 0.16= 1.7 / 3.4 X 0.16 / 3= 1/2 X 0.16 / 3= 0.08 / 3= 0.4 &#......余下全文>>
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