Question

解方程，要求完整步骤

Answer 1

令x^2-3=y

y^2+3y+2=0
y=-1 y=-2
x^2-3=-1 x^2=2 x=根号2 x=-根号2
x^2-3=-2 x^2=1 x=1 x=-1

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Answer 2

（x²-3)²-3(3-x²)+2=0
(x²-3)²+3(x²-3)+2=0
[(x²-3)+2][(x²-3)+1]=0
(x²-1)(x²-2)=0
(x+1)(x-1)(x+√2)(x-√2)=0
x=±1,±√2