
数学题目
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解﹕
⑶2x=±﹙x+1﹚∴x=1或x=﹣1∕3;
⑷2x²-x-6=0∴﹙x-2﹚﹙2x+3﹚=0∴x-2=0或2x+3=0∴x=1或x=﹣3∕2;
⑸x²﹣x+1∕4=5∕4∴﹙x-½﹚²=5∕4∴x-½=±√5∕2∴x=﹙1±√5﹚∕2;
⑹﹙x+1﹚﹙x-5﹚=0∴x+1=0或x-5=0∴x=﹣1或x=5;
⑺2x²-2√2x+1=2∴﹙√2x-1﹚²=2∴√2x-1=±√2∴x=﹙√2±2﹚∕2;
⑻a=2﹐b=7﹐c=﹣3﹐Δ=b²-4ac=7²-4×2×﹙﹣3﹚=73>0﹐∴x=﹙﹣b±√Δ﹚∕﹙2a﹚=﹙﹣7±√73﹚∕4;
⑼3﹙x-2﹚²-x﹙x-2﹚=0∴[3﹙x-2﹚-x]﹙x-2﹚=0∴3﹙x-2﹚-x=0或x-2=0∴x=3或x=2;
⑽[﹙x+2﹚-1][﹙x+2﹚+4]=0∴﹙x+2﹚-1=0或﹙x+2﹚+4=0∴x=﹣1或x=﹣6;
⑶2x=±﹙x+1﹚∴x=1或x=﹣1∕3;
⑷2x²-x-6=0∴﹙x-2﹚﹙2x+3﹚=0∴x-2=0或2x+3=0∴x=1或x=﹣3∕2;
⑸x²﹣x+1∕4=5∕4∴﹙x-½﹚²=5∕4∴x-½=±√5∕2∴x=﹙1±√5﹚∕2;
⑹﹙x+1﹚﹙x-5﹚=0∴x+1=0或x-5=0∴x=﹣1或x=5;
⑺2x²-2√2x+1=2∴﹙√2x-1﹚²=2∴√2x-1=±√2∴x=﹙√2±2﹚∕2;
⑻a=2﹐b=7﹐c=﹣3﹐Δ=b²-4ac=7²-4×2×﹙﹣3﹚=73>0﹐∴x=﹙﹣b±√Δ﹚∕﹙2a﹚=﹙﹣7±√73﹚∕4;
⑼3﹙x-2﹚²-x﹙x-2﹚=0∴[3﹙x-2﹚-x]﹙x-2﹚=0∴3﹙x-2﹚-x=0或x-2=0∴x=3或x=2;
⑽[﹙x+2﹚-1][﹙x+2﹚+4]=0∴﹙x+2﹚-1=0或﹙x+2﹚+4=0∴x=﹣1或x=﹣6;
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