Question

c++用*编写菱形

c++用*编写菱形
输入一个数字即可得到相对应边长的菱形
要求语句简单，简短

Answer 1

#include<iostream.h>
#include<iomanip.h>
int main()
{
int i, j;
int t, n;
cin>>n;
for(i=1; i<=n; i++)
{
cout<<setw(n-i+1);
for(j=1; j<=2*i-1; j++)
{
cout<<"*";
}
cout<<endl;
}
for(i=n-1; i>0; i--)
{
cout<<setw(n-i+1);
for(j=1; j<=2*i-1; j++)
{
cout<<"*";
}
cout<<endl;
}
return 0;
}

Answer 2

#include<iostream.h>#include<math.h>void main(){ int n,t,b,k,j; cin>>n; t=(n+1)/2; for(k=1;k<=n;k++){ b=abs(k-t); for(j=1;j<=b+10;j++) cout<<" "; for(j=1;j<=2*(t-b)-1;j++) cout<<"*"; cout<<endl; }}

Answer 3

转载
#include<iostream>
using namespace std;
main()
{
int m,i,j,k,h;
cout <<"请输入菱形的边长：\n";
cin>>m;
for(i=0;i<m;i++)
{
for(j=0;j<m-i-1;j++)
{
cout<<" ";
}
if(i==0)
{
cout<<"*\n";
continue;
}
{
cout<<"*";
for(k=0;k<i;k++)
{
cout<<" ";
}
cout<<' ';
for(h=0;h<i-1;h++)
cout<<" ";
cout<<'*'<<endl;
}
}
i--;
--i;
for(i;i>-1;i--)
{
for(j=0;j<m-i-1;j++)
{
cout<<" ";
}
if(i==0)
{
cout<<"*\n";
continue;
}
{
cout<<"*";
for(k=0;k<i;k++)
{
cout<<" ";
}
cout<<' ';
for(h=0;h<i-1;h++)
cout<<" ";
cout<<'*'<<endl;
}
}
}