Question

C#提取IP地址的各个组成部分

C#提取IP地址的各个组成部分,如输入IP地址为 172.0.0.1 输出结果为170 0 0 1提示:用string 类的Split()方法 哪位高手能帮我

Answer 1

static void Main(string[] args)
{
string a;
Console.WriteLine("请输入IP地址:");
a = Console.ReadLine();
string[] b = a.Split('.');
foreach (string c in b)
{
Console.Write(c);
Console.Write(" ");
}
Console.ReadLine();
}

Answer 2

static void Main(string[] args)
        {
            string a;
            Console.WriteLine("请输入IP地址:");
            a = Console.ReadLine();
            string[] b = a.Split('.');
            foreach (string c in b)
            {
                Console.Write(c);
                Console.Write(" ");
            }
            Console.ReadLine();
        }

通过对于“.”的匹配对数据进行处理

Answer 3

string strip="172.0.0.1";string[] ips=strip.split(".")Console.WriteLine("{0} {1} {2} {3}",ips[0],ips[1],ips[2],ips[3]);

Answer 4

string str = "127.0.0.1";
string[] result = str.Split('.'); foreach (string s in result)
{
Console.WriteLine(s);
}

Answer 5

string s="172.0.0.1";string[] sArray=s.Split('.');foreach(string i in sArray)
Console.WriteLine(i.ToString());