Question

求解过程啊啊啊啊啊啊啊啊

Answer 1

∠abc=∠acb=70°所以∠bac等于40° ab×ab=bd×ce 所以ab/bd=ce/ab 又因为ab=ac，所以
ce/ab=ac/db,所以三角形abd与三角形ace相似，所以∠cae=∠bda所以∠bda+∠dba=∠dba＋∠cae=180°-70°=110°。所以∠dae=40°＋110°=150°

Answer 2

∵ AB=AC
∴∠ABC=∠ACB=70
∠ABD=∠ACE
∵AB^2=DB*CE 即AB：CE=DB：AC
∴△ABD ≌ △ECA
∠BAD=∠AEC ∠CAE=∠ADB

∠DAE=∠BAC+∠BAD+∠CAE
=∠BAC+（∠BAD+∠ADB）
=180-2∠ABC+∠ABC
=180-∠ABC
=180-70
=110