Question

4根号6-4根号1/2+3根号8

4根号6-4根号1/2+3根号8
2根号12×根号3/4÷3根号2
（根号2+1）的平方（2根号2-3）

Answer 1

4根号6-4根号1/2+3根号8
=4√6-4√(1/2)+3√8
=4√6-4√(2/4)+3×√4×√2
=4√6-4×√2×√(1/4)+3×2×√2
=4√6-4×√2×1/2+6√2
=4√6-2√2+6√2
=4√6+4√2

2根号12×根号3/4÷3根号2
=2√12×√(3/4)÷3√2
=(2÷3)×√(12×3/4÷2)
=(2/3)×√(9/2)
=(2/3)×√9×√(1/2)
=(2/3)×3×√(2/4)
=2×√2×√(1/4)
=2√2×1/2
=√2

(根号2+1)²(2根号2-3)
=(√2+1)²(2√2-3)
=(√2²+2√2+1²)(2√2-3)
=(2√2+3)(2√2-3)
=(2√2)²-3²
=8-9
=-1

Answer 2

4√6-4√(1/2)+3√8=4√6-(4√2)/2+3*2√2=4√6-2√2+6√2=4√6+4√2

(2√12)*(√《3/4》)÷3√2=4√3*(√3/2)(√2/6)=(4*√3*√3*√2)/(2*6)=√2

[(√2+1)^2][2√2-3]=(2+2√2+1)(2√2-3)=(2√2+3)(2√2-3）=8-9=-1