化简：x+2分之x²+2x+1除以x-1分之x²-1-x+2分之x
展开全部
(x²+2x+1)/(x+2)÷(x²-1)/(x-1)-x/(x+2)
=(x+1)²/(x+2)÷[(x-1)(x+1)/(x-1)]-x/(x+2)
=(x+1)²/(x+2)÷[(x-1)(x+1)/(x-1)]-x/(x+2)
=(x+1)²/(x+2)÷(x+1)-x/(x+2)
=(x+1)²/(x+2)×1/(x+1)-x/(x+2)
=(x+1)/(x+2)-x/(x+2)
=(x+1-x)/(x+2)
=1/(x+2)
=(x+1)²/(x+2)÷[(x-1)(x+1)/(x-1)]-x/(x+2)
=(x+1)²/(x+2)÷[(x-1)(x+1)/(x-1)]-x/(x+2)
=(x+1)²/(x+2)÷(x+1)-x/(x+2)
=(x+1)²/(x+2)×1/(x+1)-x/(x+2)
=(x+1)/(x+2)-x/(x+2)
=(x+1-x)/(x+2)
=1/(x+2)
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
