Question

数学计算题：要过程

(-1/2)×(-2)=？ （-1又1/2）×（-1又1/3）×（-1又1/4）×（-1又1/5）-（-1又1/6）×(-1又1/7)=？

Answer 1

(-1/2)×(-2)=1
（-1又1/2）×（-1又1/3）×（-1又1/4）×（-1又1/5）-(???)（-1又1/6）×(-1又1/7)

=（-3/2）×（-4/3）×（-5/4）×（-6/5）-（-7/6）×(-8/7)
= 3/2× 4/3× 5/4 × 6/5 - 7/6 × 8/7
= 6/2 - 8/6
= 3- 4/3
= 1又3分之2

Answer 2

(-1/2)×(-2)
=1/2×2
=1

原式=(3/2×4/3×5/4×6/5)-(7/6×8/7)
=3-4/3
=1又2/3

Answer 3

(-1/2)×(-2)=1
（-1又1/2）×（-1又1/3）×（-1又1/4）×（-1又1/5）-（-1又1/6）×(-1又1/7)
=（-3/2）*（-4/3）*（-5/4）*（-6/5）*（-7/6）*（-8/7）
=8/2=4