Question

分解因式:4(a-b)^2-16(a+b)^2

有过程!!!

Answer 1

4(a-b)^2-16(a+b)^2

=[2(a-b)+4(a+b)][2(a-b)-4(a+b)]
=(6a+2b)(-2a-6b)
=-4(3a+b)(a+3b)

Answer 2

解
4(a-b)²-16(a+b)²
=4[(a-b)²-4(a+b)²]
=4[(a-b)+2(a+b)][(a-b)-2(a+b)]
=4(3a+b)(-a-3b)
=-4(3a+b)(a+3b)