急求解啊急求解啊急求解啊!!!!!
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∵AM是△ABC的中线
∴BM=CM=CE+EM
∵AE是△ABC的高线
∴AB2=BE2+AE2,AC2=AE2+CE2,AM2=ME2+AE2
∴AB2+AC2
=BE2+AE2+AE2+CE2
=(BM+ME)2+AE2+AE2+(CM-ME)2
=(BM+ME)2+AE2+AE2+(BM-ME)2
=BM2+2BMME+ME2+AE2+AE2+BM2-2BMME+ME2
=2BM2+2AE2+2ME2
=2BM2+2(AE2+ME2)
=2BM2+2AME2
∴BM=CM=CE+EM
∵AE是△ABC的高线
∴AB2=BE2+AE2,AC2=AE2+CE2,AM2=ME2+AE2
∴AB2+AC2
=BE2+AE2+AE2+CE2
=(BM+ME)2+AE2+AE2+(CM-ME)2
=(BM+ME)2+AE2+AE2+(BM-ME)2
=BM2+2BMME+ME2+AE2+AE2+BM2-2BMME+ME2
=2BM2+2AE2+2ME2
=2BM2+2(AE2+ME2)
=2BM2+2AME2
追答
∵AM是△ABC的中线
∴BM=CM=CE+EM
∵AE是△ABC的高线
∴AB2=BE2+AE2,AC2=AE2+CE2,AM2=ME2+AE2
∴AB2+AC2
=BE2+AE2+AE2+CE2
=(BM+ME)2+AE2+AE2+(CM-ME)2
=(BM+ME)2+AE2+AE2+(BM-ME)2
=BM2+2BMME+ME2+AE2+AE2+BM2-2BMME+ME2
=2BM2+2AE2+2ME2
=2BM2+2(AE2+ME2)
=2BM2+2AME2
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