Question

已知X=√2+1，求（x²-x分之x-1-x²-2x+1分之x）÷x分之1的值要过程 好的给赏！！！

Answer 1

原式=[(x-1)/x(x-1)-x/(x-1)²]*x
=[1/x-x/(x-1)²]*x
=1/x*x-x/(x-1)²*x
=1-x²/(x²-2x+1)
=(x²-2x+1-x²)/(x²-2x+1)
=(-2x+1)/(x-1)²
=(-2√2-2+1)/(√2+1-1)
=(-2√2-1)/√2
=(-4-√2)/2

追答

我不上QQ
用百度Hi联系吧

哦，千米错了一点，对不起
原式=[(x-1)/x(x-1)-x/(x-1)²]*x
=[1/x-x/(x-1)²]*x
=1/x*x-x/(x-1)²*x
=1-x²/(x²-2x+1)
=(x²-2x+1-x²)/(x²-2x+1)
=(-2x+1)/(x-1)²
=(-2√2-2+1)/(√2+1-1)²
=(-2√2-1)/2