Question

总是提示syntax error... 谁知道错误出在哪里。。。各位大神帮忙看一下 谢谢啦

#include <stdio.h>
char precedence get_token(char *symbol, int *n)
main()
{
#define MAX_STACK_SIZE 100
#define MAX_EXPR_SIZE 100
typedef enum{lparen ,rparen, plus, minus, times, divide,
mod, eos, operand} precedence;
int stack[MAX_STACK_SIZE];
char expr[MAX_EXPR_SIZE];
int eval(void);
{
/* evlauste a postfix expression,expr,maintained as a
global variable.'\0'is the end of the expression.
The stack and top of the stack are golbla variables.
get_token is used to return the tokentype and
the character symblo.Operands are assumed to be single
character digits */
precedence token;
char symbol;
int op1,op2;
int n = 0;/* counter for the expression string */
int top = -1;
token = get_token(&symbol,&n);

while(token != eos)
{
if(token == operand)
add(&top,symbol-'0'); /* stack insert */
else
{
/* remove two operands,perform operation,and
return result to the stack*/
op2 = delete(&top); /*stack delete */
op1 = delete(&top);
switch(token)
{
case plus: add(&top,op1+op2);
break;
case minus: add(&top,op1-op2);
break;
case times: add(&top,op1*op2);
break;
case divide: add(&top,op1/op2);
break;
case mod: add(&top,op1%op2);
}
}
token = get_token(&symbol,&n);
}
return delete(&top); /* return result */
}
precedence get_token(char *symbol, int *n)
{
*symbol = expr[(*n)++];
switch(*symbol){
case '(': return lparen;
case ')': return rparen;
case '+': return plus;
case '-': return minus;
case '*': return times;
case '/': return divide;
case '%': return mod;
case ' ': return eos;
default : return operand; /* no error checking,default is operand */
}
}
}

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Answer 1

你应该把具体错误信息也贴出来

追问

error C2061: syntax error : identifier 'get_token'
error C2059: syntax error : ';'
error C2059: syntax error : 'type'

追答

precedence是啥？

追问

声明的枚举类型 亲

追答

你包含对应的头文件没有？报错的似乎和这个类型找不到有关

而且：char precedence get_token
get_token前面为什么有两个类型？这显然语法错误