Question

已知f（x）=x5-ax3+bx+2，且f（-5）=17，则f（5）的值为？

x后的数为幂

Answer 1

f（-5）=x5-ax3+bx+2=17;
所以x5-ax3+bx=15

f（5）=-(x5-ax3+bx)+2=-15+2=-13

Answer 2

-13 f(-5) = 17 推出 -23+15a-5b = 17 也就是15a-5b =40 f(5) = 27-15a+5b = 27-(15a-5b) = 27-40 =-13

Answer 3

好学的孩子