Question

c语言如何获取当前日期和时间并全部转化成数字

比如 20131014015835

这样：
2013 年

10 月

14 日

01 时

58 分

35 秒
C++也可以

Answer 1

键盘输入用： scanf("%4d%2d%2d%2d%2d%2d", &year,&mo,&day,&h,&m,&s);

#include <stdio.h>
main(){
char str[]="20131014015835";
int year,mo,day,h,m,s;
// scanf("%4d%2d%2d%2d%2d%2d", &year,&mo,&day,&h,&m,&s);
sscanf(str,"%4d%2d%2d%2d%2d%2d", &year,&mo,&day,&h,&m,&s);
printf("%4d Nian\n%02d Yue\n%02d Ri\n%02d Shi\n%02d Fen\n%02d Miao\n",
year,mo,day,h,m,s);

}

追问

你没看清楚我的要求

Answer 2

#include<time.h>
#include<stdio.h>
int main()
{
    char buf[BUFSIZ];
    time_t t = time(NULL);
    struct tm* now = localtime(&t);
    strftime(buf,BUFSIZ,"%Y%m%d%H%M%S",now);
    puts(buf);
}