Question

用JAVA正则表达式提取javascript函数体

现在有一段JS，如下，需要把里面的function分别提取出来。
function user(username) {
var value = "username : ${username}";
}

function article(article) {
var article = "article : ${article}";
for (var i = 0; i < 10; i++) {
article += i;
}
}

function channel(channel) {
if (channel != null) {
alert("channel is not null !");
}
}

我要传入一个参数，比如article ，就可以提取出
function article(article) {
var article = "article : ${article}";
for (var i = 0; i < 10; i++) {
article += i;
}
}
这个函数... 求大神帮忙！~

Answer 1

Pattern regex = Pattern.compile("function\\s*?article\\(.*?\\)\\s*?\\{[^{}]*?(\\{.*?\\})*[^{}]*?\\}", Pattern.DOTALL | Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE | Pattern.MULTILINE);

把里面的article替换成你的参数就可以了

Answer 2

public void xxx(){//
File f=new File("funJS.js");
String temp=null;
String sou="";
try {
BufferedReader in=new BufferedReader(new FileReader(f));
while((temp=in.readLine())!=null){
sou+=temp;
}
} catch (Exception e) {
e.printStackTrace();
}
String source="function xx(){xx{}xx{}} function ww(){}";
//String reg2=".*?(function\\s+\\w+\\(\\)\\{\\})";
String reg="function\\s+\\w+\\(\\s*\\w*\\s*\\)\\s*\\{([^\\{\\}]*?(\\{[^\\{\\}]*\\})*)*\\}";
System.out.println(reg);
Pattern p=Pattern.compile(reg,Pattern.MULTILINE);
Matcher m=p.matcher(sou);
System.out.println(source.matches(reg));
System.out.println("………………function get ^_^");
while(m.find()){

System.out.println(m.group(0));
}
}