Question

python中如何得到一组循环的数

比如 有1234 得到2341 3412 4123

Answer 1

def cycle(num):        #产生某一数字的所有循环数
	strNum = str(num)
	length = len(strNum)
	cycle_all = []
	for i in range(length):
		number = int(strNum[i:] + strNum[:i])
		cycle_all.append(number)
	return cycle_all
if __name__ == '__main__':
	for i in cycle(1234):
		print i,

Answer 2

def cycle_list(num):
s=str(num)
return [int(s[i:]+s[:i]) for i in range(len(s))]

cycle_list(1234567)
#[1234567, 2345671, 3456712, 4567123, 5671234, 6712345, 7123456]

Answer 3

foo = "1234"
for i in range(len(foo)):
    print(foo[i:] + foo[:i])

Answer 4

Easy ;)

a = [1,2,3,4,5] # put in whatever you like

for i in range(len(a)):
print a[i:]+a[:i]

I recommend you have more reading about the python list object,
you'll be surprised of what it can give you