Question

Asp.net GridView点击编辑后，编辑框显示原数据方法？

我希望点击Gridview中的编辑后，原来的数据自动显示在编辑框中，以及下拉框选中原来的数据！之前有在某网页上看到过方法，现在找不到了。求帮忙！

Answer 1

 <asp:TemplateField HeaderText="下拉框">
                         <ItemTemplate>
                            <asp:Label ID="lbl" runat="server" Text='<%# Eval("DataField") %>'></asp:Label>
                         </ItemTemplate>
                         <EditItemTemplate>
                            <asp:DropDownList ID="ddl" runat="server" DataSource='<%# ddlBind() %>'></asp:DropDownList>
                         </EditItemTemplate>
                      </asp:TemplateField>
<asp:TemplateField HeaderText="文本框">
                         <ItemTemplate>
                            <asp:Label ID="lbl" runat="server" Text='<%# Eval("DataField") %>'></asp:Label>
                         </ItemTemplate>
                         <EditItemTemplate>
                            <asp:TextBox ID="txt" runat="server" DataSource='<%# Bind("DataField") %>'></asp:DropDownList>
                         </EditItemTemplate>
                      </asp:TemplateField>
<asp:TemplateField HeaderText="复选框">
                         <ItemTemplate>
                            <asp:Label ID="lbl" runat="server" Text='<%# Eval("DataField") %>'></asp:Label>
                         </ItemTemplate>
                         <EditItemTemplate>
                            <asp:CheckBox ID="cbkReveal1" runat="server" Checked='<%# DataBinder.Eval(Container.DataItem,"DataField") %>' />                         </EditItemTemplate>
                      </asp:TemplateField>

是不是这种？？

那个ddlBind()是你后台代码的一个方法