Question

已知x=3+2√2，y=3-2√2，求x²y+xy²的值

Answer 1

知x=3+2√2，y=3-2√2，求
xy = 9 - 8 = 1
x +y = 3 +3 = 6

x²y+xy²
= xy (x +y )
= 1 x 6
= 6

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Answer 2

解:
x^2y+xy^2
=xy(x+y)
=(3+2√2)(3-2√2)(6)
=(9-8)(6)=6