Question

如何用java获得xml文件中标签的属性列表值？

1.有xmlcount.xml文件。文件的内容如下：
<?xml version="1.0" encoding="UTF-8"?>
<count-object-inf month-count="34" total-count="34" temp-count="0" week-count="34" day-count="16" year-count="34"><date>2010-11-26T11:30:10.234+08:00</date></count-object-inf>

现在我想通过java去读取xmlcount.xml文件，然后获得其中标签名为：count-object-inf的多个属性，请问怎么做？

Answer 1

import java.io.*;
import java.util.*;
import org.jdom.*;
import org.jdom.input.*;public class MyXMLReader2JDOM {
public static void main(String arge[]) {
long lasting = System.currentTimeMillis();
try {
SAXBuilder builder = new SAXBuilder();
Document doc = builder.build(new File("xmlcount.xml"));
Element foo = doc.getRootElement();
// List allChildren = foo.getChildren();

System.out.print( foo.getAttributeValue("month-count"));
System.out.println(foo.getAttributeValue("total-count"));

} catch (Exception e) {
e.printStackTrace();
}
}
}