Question

求C语言大神，在线等啊

题目是这个

#include <stdio.h>#include <stdlib.h>void main(){ int i,sum; printf ("Please enter num:"); scanf("%d",&i); if (i<=750) printf("sum=i*0.01"); else if (i>750&&i<=2250) printf("sum=7.5+(i-750)*0.02"); else if(i>250&&i<=3750) printf("sum=37.5+(i-2250)*0.03"); else if(i>3750&&i<5250) printf("sum=82.5+(i-3750)*0.04"); else if(i<7000&&i>=5250) printf("sum =142.5+(i-5250)*0.05"); else printf("sum=230+(i-7000)*0.06");} 求大神解答我哪里做错了啊 拜托拜托 我在线等啊

Answer 1

#include <stdio.h>

#include <stdlib.h>

void main()

{

  int i;

  printf ("Please enter num:");

  scanf("%d",&i);

  if (i<=750)

  printf("sum=%f",i*0.01);    //i乘以一个小数肯定是float或者double型，所以用%f输出

  else if (i>750&&i<=2250)

  printf("sum=%f",7.5+(i-750)*0.02);

  else if(i>250&&i<=3750)

  printf("sum=%f",37.5+(i-2250)*0.03);

  else if(i>3750&&i<5250)

  printf("sum=%f",82.5+(i-3750)*0.04);

  else if(i<7000&&i>=5250)

  printf("sum =%f",142.5+(i-5250)*0.05);

  else

  printf("sum=%f",230+(i-7000)*0.06);

}

Answer 2

#include <stdio.h>
#include <stdlib.h>
void main()
{
int i;
float sum;
printf ("Please enter num:");
scanf("%d",&i);
if (i<=750)
printf("sum=%f\n",i*0.01);
else if (i>750&&i<=2250)
printf("sum=%f\n",7.5+(i-750)*0.02);
else if(i>250&&i<=3750)
printf("sum=%f\n",37.5+(i-2250)*0.03);
else if(i>3750&&i<5250)
printf("sum=%f\n",82.5+(i-3750)*0.04);
else if(i<7000&&i>=5250)
printf("sum =%f\n",142.5+(i-5250)*0.05);
else
printf("sum=%f\n",230+(i-7000)*0.06);
}