Question

(-x+2x²+5)+(4x²-3-6x)等于多少

还有(3a²-ab+7)-(-4a²+2ab+7)

Answer 1

(-x+2x²+5)+(4x²-3-6x)等于多少
=-x+2x²+5+4x²-3-6x
=6x²-7x+2;

问题补充：
还有(3a²-ab+7)-(-4a²+2ab+7)
=3a²-ab+7+4a²-2ab-7
=7a²-3ab;
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Answer 2

(-x+2x²+5)+(4x²-3-6x)等于多少
= -x+2x²+5+4x²-3-6x
= 2+6x²-7x

(3a²-ab+7)-(-4a²+2ab+7)
= 3a²-ab+7+4a²-2ab-7
= 7a²-3ab

Answer 3

(-x+2x²+5)+(4x²-3-6x)
=-x+2x²+5+4x²-3-6x
=6x²-7x+2
(3a²-ab+7)-(-4a²+2ab+7)

=3a²-ab+7+4a²-2ab-7

=7a²-3ab

Answer 4

1. 原式=-x+2x^2+5+4x^2-3-6x=6x^2-7x+2

2. 原式=3a^2-ab+7+4a^2-2ab-7=7a^2-3ab