
化简:2(x²-xy)-3(2x²-3xy)-2[x²-2x²-xy+y²)]
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2(x²-xy)-3(2x²-3xy)-2[x²-2x²-xy+y²)]
= 2x^2 -2xy - 6x^2 + 9xy - 2x^2 +4x^2 + 2xy - 2y^2
= -2x^2 + 9xy -2y^2
= 2x^2 -2xy - 6x^2 + 9xy - 2x^2 +4x^2 + 2xy - 2y^2
= -2x^2 + 9xy -2y^2
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