Question

求大神解答大一的无机化学问题，内附答案，求过程，谢谢~~

Answer 1

4-11、求速率常数
ln (k2 /k1) = (Ea / R)( 1/ T1 - 1/T2 )
ln(k2 / 2.37*10^-2) = (163 *1000/ 8.314) ( 1/ 390 - 1/ 420)
k2 = 0.859
4-12、求活化能范围
ln (k2 /k1) = (Ea / R)( 1/ T1 - 1/T2 )
当T2 = T1 + 10，若：T1 = 300K ，T2 = 310K
(1) k2 = 2k1
求Ea1
ln (2k1 /k1) = (Ea / 8.314)( 1/ 300 - 1/310 )
Ea1 = 53.59 kJ/mol
(2) k2 = 4k1
求Ea2
ln (4k1 /k1) = (Ea / 8.314)( 1/ 300 - 1/310 )
Ea2 = 107.19 kJ/mol