2013-10-21
展开全部
恭喜你,我又给你做了个函数的,(已试过)假设1.11在A2格,在b2输入=TEXT(INT(B3),"[DBNUM2]")&"元"&IF(INT(B3)=B3,"整",(IF(INT(B3*10)-INT(B3)*10>0,TEXT(INT(B3*10)-INT(B3)*10,"[DBNUM2]")&"角","零")&IF(B3*100-INT(B3*10)*10>0,TEXT(INT(B3*100-INT(B3*10)*10),"[DBNUM2]")&"分","")))
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2013-10-21
展开全部
http://user.qzone.qq.com/59117348/blog/1206972932=IF(A1=0,0,IF(TRUNC(A1)=A1,TEXT(TRUNC(A1),"[dbnum2]G/通用格式"&"元整"),IF(TRUNC(ROUND((A1-INT(A1))*10,2))=ROUND((A1-INT(A1))*10,2),TEXT(TRUNC(A1),"[dbnum2]G/通用格式"&"元")&TEXT(TRUNC(ROUND((A1-INT(A1))*10,2)),"[dbnum2]G/通用格式"&"角整"),TEXT(TRUNC(A1),"[dbnum2]G/通用格式"&"元")&TEXT(TRUNC(ROUND((A1-INT(A1))*10,2)),"[dbnum2]G/通用格式"&"角")&TEXT((ROUND((A1-INT(A1))*10,2)-TRUNC(ROUND((A1-INT(A1))*10,2)))*10,"[dbnum2]G/通用格式"&"分"))))
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2013-10-21
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