Question

用配方法解方程:2x^2-4x+1=0

Answer 1

2x^2-4x+1=0 所以2(x^2-2x)+1=0 2(x-1)^2-2+1=0 2(x-1)^2=1 (x-1)^2=1/2 x-1=正负根号2/除以2。。。。。

Answer 2

2x^2-4x+1=0 2(x-1)�0�5=1 x-1=±根号2 /2 x=1±根号2 /2

Answer 3

2x^2-4x+1=0x^2-2x+1/2=0x^2-2x= -1/2x^2-2x+1=1-1/2(x-1)^2=1/2x-1= ±√(1/2)= ±√2/2x1=1+√2/2 x2=1-√2/2