Question

写出函数y=-x²+3x-2的单调递增区间

写出函数y=-x²+3x-2的单调递增区间，详细过程！
y=√（x-2)(x-1)的单调递减区间
y=1/(x-1)的单调区间

Answer 1

y=-(x²-3x+9/4)+1/4
=-(x-3/2)²+1/4
∵a=-1<0
∴x<3/2时y随x的增大而增大
∴单调递增区间是(-无穷大,3/2)