Question

C++中用new创建动态结构数组并同时初始化输出问题？

#include<iostream>
#include<string>
using namespace std;

struct CandyBar
{char name[20];
double wight;
int ka;
};

int main()
{int i;
CandyBar * ps=new CandyBar[2];
*ps=
{
{"Mocha Munch",2.3,350},
{"xiao sheng",5.1,888},
{"xiao qiang",5.0,666}
};
for(i=0;i<3;i++)
{cout<<(ps+i)->name<<endl<<(ps+i)->wight<<endl<<(ps+i)->ka<<endl;};
delete [] ps;
return 0;
}

如何给CandyBar[2]初始化并全部输出动态数组啊？小弟是新手希望各位前辈能帮我把程序改好，我不是没动脑筋，但是我做到上面就真的不会了，拜托各位了，谢谢啊~！

Answer 1

#include<iostream>
#include<string>
using namespace std;

struct CandyBar
{
char name[20];
double wight;
int ka;
};

int main()
{
int i;
CandyBar *ps =(CandyBar*) new CandyBar[3];
// *ps = {"MochaMunch",2.3,350};
// ps[1] = {"xiaosheng",5.1,888};
// ps[2] = {"xiaoqiang",5.0,666};
strcpy((ps+0)->name, "CandyBar");
(ps+0)->wight = 100;
(ps+0)->ka = 100;
for(i=0;i<3;i++)
{
cout<<(ps+i)->name<<endl<<(ps+i)->wight<<endl<<(ps+i)->ka<<endl;
}
delete []ps;
return 0;
}

照个上面的
strcpy((ps+0)->name, "CandyBar");
(ps+0)->wight = 100;
(ps+0)->ka = 100;
写剩余的两个了