Question

2x的3次方—5x的2次方+4x—1=0

快

Answer 1

解：2x^3 - 5x^2 + 4x -1 = 0 (2x^3- 2x^2) - (3x^2 - 3x) +(x -1) = 0 (x-1)(2x^2 - 3x +1) = 0 (x-1)( 2x-1)(x-1) = 0 (2x - 1)(x -1)^2 = 0 x1 = 1/2 x2=x3 = 1

Answer 2

2x的3次方—5x的2次方+4x—1=02x的3次方-2x的2次方-3x的2次方+4x—1=02x的2次方（x-1）-（3x—1）（x-1）=0（x-1）（2x的2次方-3x+1）=0（x-1）（2x—1）（x-1）=0x=1/2（二分之一）或x=1

Answer 3

分解因式2x^2-2x^2-3x^2+4x-1=02x^2(x-1)-(3x-1)(x-1)=0(2x^2-3x+1)(x-1)=0(2x-1)(x-1)^2=0x=1/2x=1