Question

(x^2+x)^2-1在实数范围内因式分解

^代表幂
因式分解最终结果应该是未知数x是一次

Answer 1

=(x*x+x+1)*(x*x+x-1)=[(x+0.5)*(x+0.5)+0.75]*[(x+0.5)*(x+0.5)-1.25]

Answer 2

(x^2+x+1)*(x+(1+5^0.5)/2)*(x+(1-5^0.5)/2)

Answer 3

[X(X+1)+1][(X+1)(X-1)+X]