Question

分解因式，必采纳

Answer 1

=(2xy-(x^2+y^2-1))(2xy+(x^2+y^2-1))
=(2xy+x^2+y^2-1))(2xy-x^2-y^2+1))
=((x+y)^2-1)(1-(x-y)^2)
=(x+y+1)(x+y-1)(1-x+y)(1+x-y)

Answer 2

4x²y²-(x²+y²信雀-1)²
=[2xy+（x²+y²-1)][2xy-（x²+y²-1)]
=(2xy+x²+y²-1)(2xy-x²-y²+1)
=[(x+y)²-1][1-(x²-2xy+y²滑桐早)]
=[(x+y)²-1][1-(x-y)²轮饥]
=(x+y+1)(x+y-1)(1+x-y)(1-x+y)