Question

解二元一次方程组x/3+y/2=13,-x/4+y/3=3

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Answer 1

x/3+y/2=13 (1)
-x/4+y/3=3 (2)
(1)*3+(2)/4
3y/2+4y/3=39+12
17y/6=51
所以
y=18
x=3(13-y/2)=12