八年级下册，数学，计算题。谢谢各位学霸大神先～
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解⑵：1-[x-1/(1-x)]²+(x²-x+1)/(x²-2x+1)=1-[(x²-x+1)/(x-1)]²+(x²-x+1)/(x²-2x+1)=1-(x²-x+1)²/(x-1)²+(x²-x+1)/(x-1)²=[(x-1)²-(x²-x+1)²+(x²-x+1)]/(x-1)²=(2x²-3x+2-x^4+2x³-3x²+2x-1)/(x-1)²=
(-x^4+2x³-x²-x+1)/(x-1)²=(x-1)(-x³+x²-1)/(x-1)²=-(x³-x²+1)/(x-1)。
解⑶：(2x+2)/x-(x+2)/(x-2)=(x²-4)/(x²-2x)，(2x+2)/x-(x+2)/(x-2)-(x²-4)/(x²-2x)=
2(x+1)/x-(x+2)/(x-2)-(x-2)(x+2)/x(x-2)=[2(x+1)(x-2)-x(x+2)-(x-2)(x+2)]/x(x-2)=x(x-4)/x(x-2)=(x-4)/(x-2)
(-x^4+2x³-x²-x+1)/(x-1)²=(x-1)(-x³+x²-1)/(x-1)²=-(x³-x²+1)/(x-1)。
解⑶：(2x+2)/x-(x+2)/(x-2)=(x²-4)/(x²-2x)，(2x+2)/x-(x+2)/(x-2)-(x²-4)/(x²-2x)=
2(x+1)/x-(x+2)/(x-2)-(x-2)(x+2)/x(x-2)=[2(x+1)(x-2)-x(x+2)-(x-2)(x+2)]/x(x-2)=x(x-4)/x(x-2)=(x-4)/(x-2)
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