Question

C#如何避免相同MDI子窗口重复打开

private void toolStripButton1_Click(object sender, EventArgs e) { foreach (Form childrenForm in this.MdiChildren) { //检测是不是当前子窗体名称 if (childrenForm.Name == "Form2") { //是的话就是把他显示 childrenForm.Visible = true; //并激活该窗体 childrenForm.Activate(); childrenForm.WindowState = FormWindowState.Maximized; return; } } //下面是打开子窗体 Form2 f2 = new Form2(); f2.MdiParent = this; f2.Show(); }
试了网上的，根本不靠谱，还是哪里我没注意？如果已打开就最大化，否则就实例化显示
求真正有用的！谢谢！

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Answer 1

private void toolStripButton1_Click(object sender, EventArgs e)
{
foreach (Form childrenForm in this.MdiChildren)
{
//检测是不是当前子窗体名称
if (childrenForm.Name == "Form2")
{
//是的话就是把他显示
childrenForm.Visible = true;
//并激活该窗体
childrenForm.Activate();
childrenForm.WindowState = FormWindowState.Maximized;
return;
}
else
{
//下面是打开子窗体
Form2 f2 = new Form2();
f2.MdiParent = this;
f2.Show();
}

}
}

Answer 2

前几天才回答过的，直接转给你吧，active后面你再加上最大化就ok了。
http://zhidao.baidu.com/question/240466014387452204.html?oldq=1