数学函数计算题，求解答过程
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BC=DC=4
Sabe=(4-x)x4/2=8-2x
Scef=x.x/2
y=x2+(8-2x)
16/2<=y>=0
8<=x2+8-2x
x>=2
0>=x2+8-2x
(x-4)(x+2)<=0
x-4>=0 x+2<=0
x>=4 x<=-2(不存在)
x-4<=0 x+2<=0
x<=4 x<=-2
x<=4
4<=x<=2
3.Sabe+Scef=8-2x+x2/2=0
y= 16-4x+x2=0
x=0
s=0
Sabe=(4-x)x4/2=8-2x
Scef=x.x/2
y=x2+(8-2x)
16/2<=y>=0
8<=x2+8-2x
x>=2
0>=x2+8-2x
(x-4)(x+2)<=0
x-4>=0 x+2<=0
x>=4 x<=-2(不存在)
x-4<=0 x+2<=0
x<=4 x<=-2
x<=4
4<=x<=2
3.Sabe+Scef=8-2x+x2/2=0
y= 16-4x+x2=0
x=0
s=0
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