Question

php伪造referer获取header,请大神指教

$refer = XXXXX
$target = XXXXX
$host = XXXXX

$fp = fsockopen($host, 80, $errno, $errstr, 30);
if(!$fp){
echo "$errstr($errno)<br />\n";
}else{
$out = "
GET $target HTTP/1.1
Host: $host
Referer: $referer
Connection: Close\r\n\r\n";

fwrite($fp, $out);
while(!feof($fp)){
echo fgets($fp, 1024);
}
fclose($fp);
}

利用以上函数,获得的却是:
302 Found
The requested resource resides temporarily under a different URI.
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我的目的是伪造referer获得某页面的location信息(因为这个页面有跳转,会检测referer),应该怎么做?(最好不用curl,我的php没安装)

Answer 1

$out那部分不能这么写

$out = "GET $target HTTP/1.1\r\nHost: $host\r\nReferer: $referer\r\nConnection: Close\r\n";

开头不能有空行，且每一行必须有换行符分隔

或者用

$out = "GET $target HTTP/1.1\r\n";
$out .= "Host: $host\r\n";
$out .= "Referer: $referer\r\n";
$out .= "Connection: Close\r\n";