Question

C#抛出异常后怎么捕捉那个异常?

public int ExecuteGetLines(string com)
{
try
{
Con.Open();
Com.CommandText = com;
Com.Connection = Con;
int i = 0;
i = Com.ExecuteNonQuery();
return i;
}
catch
{
throw new System.ArgumentException("数据库文件错误");
}
finally
{
Com.Dispose();
Con.Close();
}
}
我在另外的地方执行的时候怎么捕捉那个异常，怎么引用("数据库文件错误")这句话?

Answer 1

一看就明白了：
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;

namespace WindowsApplication1
{
public partial class Form1 : Form
{
private void MyFun()
{
throw new System.ArgumentException("数据库文件错误");
}
public Form1()
{
InitializeComponent();
}

private void button1_Click(object sender, EventArgs e)
{
try
{
MyFun();
}
catch(Exception ex)
{
MessageBox.Show(ex.Message);
}

}
}
}