求下列函数的导数
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解y'=(sin^2xcosx^2)'
=(sin^2x)'cosx^2+(sin^2x)(cosx^2)'
=2sinx(sinx)'cosx^2+(sin^2x)(-sinx^2)(x^2)'
=2sinxcosxcosx^2-2xsin^2xsinx^2
=sin2xcosx^2-2xsin^2xsinx^2
=(sin^2x)'cosx^2+(sin^2x)(cosx^2)'
=2sinx(sinx)'cosx^2+(sin^2x)(-sinx^2)(x^2)'
=2sinxcosxcosx^2-2xsin^2xsinx^2
=sin2xcosx^2-2xsin^2xsinx^2
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