Question

如图怎么求导？

如图怎么求导？使用洛必达时sin(sinx)怎么求导？

Answer 1

如图

Answer 2

=lim(x→0)[cosx-cos(sinx)*cosx]/3x²
=1/3*lim(x→0)cosx[1-cos(sinx)]/x²
因为cos0=1
所以=1/3*lim(x→0)[1-cos(sinx)]/x²
=1/3*lim(x→0)sin(sinx)*cosx/2x
=1/6*lim(x→0)sin(sinx)/x
=1/6*1
=1/6