Question

fastjson 怎么反解析 到 Map<String，Object>这种数据结构

Answer 1

public static void main(String[] args) {
//构建模拟json数据
JSONObject json = new JSONObject();
for (int i = 1; i <= 5; i++) {
json.put("key"+i, "value"+i);
}
System.out.println("json===="+json.toString());
//解析json
Map<String,Object> map = new HashMap<String,Object>();
for (String obj : json.keySet()) {
map.put(obj, json.get(obj));
}
System.out.println("map===="+map.toString());
}
最好在这边try catch下，防止出现异常!