Question

用链表实现的多项式求值.

Answer 1

闲来无事，写了一个多项式之间的加减乘除

[cpp] view plain copy
// 多项式.cpp : 定义控制台应用程序的入口点。
//

#include "iostream"
#include <stdlib.h>
#include "iostream"
#include "string"
#include "stdafx.h"
using namespace std;

class X{
public :
X();
X* build();
X* auto_build(int n);
X* multiplication(X *x1, X *x2);
X* division(X *x1, X *x2);
X* addition(X *x1, X *x2);
X* subtraction(X *x1, X *x2);
void show();
friend istream & operator >> (istream &, X *);
friend ostream & operator << (ostream &, X *);
friend istream & operator >> (istream &, X *x);
friend ostream & operator << (ostream &output, X *x);
private:
X* next;
X* other;
int exponent;
double coefficient;
int weight;