Question

设计一个程序，输入某天是几月几日，要求算出这一天是本年的第几天？

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

Answer 1

#include <iostream>

using namespace std;

int main()

{ int y,m,d,d1,i,mon[13]= {0,31,28,31,30,31,30,31,31,30,31,30,31};

  scanf("%d%d%d",&y,&m,&d);

  mon[2]+=(y%4==0&&y%100||y%400==0);

  if(y<1||m<1||m>12||d<1||d>mon[m])

  { printf("Date input error!\n");

    return 0;

  }

  for(d1=d,i=1; i<m; i++)d1+=mon[i];

  printf("%d-%d is the %dth day of %d.\n",m,d,d1,y);

  return 0;

}

Answer 2

#include<iostream>
using namespace std;
int judge_year(int );
int judge_month(int);
void main(){
int year,month,day,sum=0;
cout<<"年份：";
cin>>year;
cout<<"\n月份:";
cin>>month;
cout<<"\n日期:";
cin>>day;
if(!judge_year(year)&&month==2&&day==29){
cout<<"今年不是闰年，非法输入"<<endl;
exit(0);
}
if(judge_year(year)){
for(int i=1;i<month;i++){
if(judge_month(i)==1)
sum+=31;
else if(judge_month(i)==0)
sum+=30;
else
sum+=29;
}
sum+=day;
}
else{
for(int i=1;i<month;i++){
if(judge_month(i)==1)
sum+=31;
else if(judge_month(i)==0)
sum+=30;
else
sum+=28;
}
sum+=day;
}
cout<<"今天是这一年的第"<<sum<<"天"<<endl;
}

int judge_year(int a){
if(a%400==0||(a%100!=0&&a%4==0))
return 1;
else
return 0;
}

int judge_month(int b){
if(b==1||b==3||b==5||b==7||b==8||b==10||b==12)
return 1;
else if(b==2)
return -1;
else
return 0;
}