Question

怎么算的 求详细过程 摆公式的水狗别来 谢谢各位了

画问号过程

Answer 1

g(x) = ln x - lna - (x-a)/(ax)^(1/2) = ln x - lna - x/(ax)^(1/2) + a /(ax)^(1/2)
= ln x - lna - (x/a)^(1/2) + a^(1/2)*x^(-1/2) ( 利用(x^n)' = nx^(n-1), (lnx)'=1/x, C'=0)
g'(x) = 1/x - 0 - a^(-1/2) (1/2) x^(1/2 - 1) + a^(1/2)*(-1/2) x^(-1/2-1)
= 1/x - 1/[2(ax)^(1/2)] - a^(1/2)*/2*x^(-3/2)
= 1/x - {1/[2(ax)^(1/2)]+ a^(1/2)*/2*x^(-3/2)}