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求解啊!!
展开全部
2^(4n+1)-(4^2n+16^n)
=2^(4n+1)-[(2^2)^2n+(2^4)^n]
=2^(4n+1)-(2^4n+2^4n)
=2^(4n+1)-(2×2^4n)
=2^(4n+1)-2^(4n+1)
=0
=2^(4n+1)-[(2^2)^2n+(2^4)^n]
=2^(4n+1)-(2^4n+2^4n)
=2^(4n+1)-(2×2^4n)
=2^(4n+1)-2^(4n+1)
=0
追问
后面两步有点看不懂呢
好吧。。我会了
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