Question

当a为任意实数时,直线ax+y-8=0恒过定点P,则以点P为焦点的抛物线的标准方...

当a为任意实数时,直线ax+y-8=0恒过定点P,则以点P为焦点的抛物线的标准方程是( )A.y2=32xB.x2=32yC.y2=-32xD.x2=-32y

Answer 1

∵a为任意实数时,直线ax+y-8=0恒过定点P,
∴x=0,y=8,
即定点P(0,8);
∴点P(0,8)为焦点的抛物线的标准方程是x2=32y.
故选B.